## Which aqueous solution has the lowest freezing point c6h12o6, c2h5oh, ch3cooh, or nacl?

Question

Which aqueous solution has the lowest freezing point c6h12o6, c2h5oh, ch3cooh, or nacl?

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1. Depression of a freezing point of the solutions depends on the number of particles of the solute in the solution.
1 mol of C6H12O6 after dissolving in water still be 1 mol, because C6H12O6 does no dissociate in water.
1 mol of C2H5OHafter dissolving in water still be1 mol, because C2H5OH does no dissociate in water.
1 mol of NaClafter dissolving in water gives2mol of particles (ions), because NaCl is a strong electrolyte(as salt) and completelydissociates in water.
NaCl —–>Nau207a + Clu207b
1 mol of CH3COOHafter dissolving in water gives more than1 mol but less than 2 moles, because CH3COOHis a weak electrolyte (weak acid) and dissociatesonly partially.

So, most particles of the solute is going to be in the solution of NaCl,
sothe lowest freezing point has the aqueous solution of NaCl.

2. Among Cu2086Hu2081u2082Ou2086, Cu2082Hu2085OH, CHu2083COOH, and NaCl, NaCl is the one that will provide the aqueous solution with the lowest freezing point.

We have 4 aqueous solutions and we want to determine which has the lowest freezing point.

• Cu2086Hu2081u2082Ou2086
• Cu2082Hu2085OH
• CHu2083COOH
• NaCl

### What is the freezing point depression?

Freezing-point depression is a drop in the temperature at which a substance freezes, caused when a smaller amount of another, non-volatile substance is added.

We can calculate the freezing point depression (u0394T) using the following expression.

u0394T = Kf x b x i

where,

• Kf is the cryoscopic constant for water.
• b is the molality of the solution.
• i is the Van’t Hoff factor.

Assuming all the solutions have the same molality, the freezing point depression will be a function of the van’t Hoff factor.

### What is the van’t Hoff factor?

The van ‘t Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass.

• For non-electrolytes, such as Cu2086Hu2081u2082Ou2086 and Cu2082Hu2085OH, i = 1.
• Comparing NaCl and CHu2083COOH, we can determine that i(NaCl) > i(CHu2083COOH) because NaCl is a strong electrolyte and CHu2083COOH a weak one.

Thus, NaCl, with the highest Van’t Hoff factor, will have the lowest freezing point.

Among Cu2086Hu2081u2082Ou2086, Cu2082Hu2085OH, CHu2083COOH, and NaCl, NaCl is the one that will provide the aqueous solution with the lowest freezing point.