What is the sum of the geometric sequence 2, 8, 32, … if there are 8 terms? 21,845 43,690 65,535 87,380 Question What is the sum of the geometric sequence 2, 8, 32, … if there are 8 terms? 21,845 43,690 65,535 87,380 in progress 0 All 7 months 2022-04-28T23:10:34+00:00 2022-04-28T23:10:34+00:00 1 Answer 0

## Answers ( 1 )

Answer:The answer is B. 43,690

Step-by-step explanation:S = 2 * 4^0 + 2 * 4^1 + 2 * 4^2 + … + 2 * 4^7

S * 4 = 2 * 4^1 + 2 * 4^2 + … + 2 * 4^7 + 2 * 4^8

4S – S = 2 * 4^8 – 2 * 4^0

3S = 2 * (4^8 – 1)

S = (2/3) * (4^8 – 1)

S = (2/3) * (2^16 – 1)

S = (2/3) * (65535)

S = 43690