## What is the remaining concentration of the cation that precipitates first, when the other cation just begins to precipitate? consider a solu

Question

What is the remaining concentration of the cation that precipitates first, when the other cation just begins to precipitate? consider a solution that is 2.3×10−2 m in fe2+ and 2.0×10−2 m in mg2+?

in progress 0

1. The remaining concentration is [tex][Fe^2^+] = 9 times 10^-^8 M; when; Mg^2^+ ions ; precipitate[/tex]

### What is a cation?

A cation is an ion that contains a positive charge. It gains a positive charge by donating an electron.

The equilibrium concentration for [tex]FeCO_3 = 3.07 times 10^-^1^1[/tex]

The equilibrium concentration for [tex]MgCO_3 = 6.82 times 10^-^6[/tex]

[tex]Fe^2^+[/tex] will precipitate first

[tex]FeCO_3 = [Fe^2^+][CO_3^2^-][/tex]

[tex]3.07 times 10^-^1^1 = (2.3 times10^-^2) [CO_3^2^-][/tex]

[tex][CO_3^2^-] = 1.33 times 10^-^9 M[/tex] to precipitate [tex]Fe^2^+[/tex] ions

[tex]MgCO_3 = [Mg^2^+][CO_3^2]6.82 times 10^-^6 = (2.0 times 10^-^2) [CO_3^2-][CO_3^26-] = 3.4 times 10^-^4 M to; precipitate; the ;Mg^2^+ ions[/tex]

[tex]FeCO_3 = [Fe^2^+][CO_3^2^-][/tex]

[tex]3.07 times 10^-^11= [Fe^2^+] (3.4 times 10^-^4)[/tex]

[tex][Fe^2^+] = 9 times 10^-^8 M; when; Mg^2^+ ions ; precipitate[/tex]

The remaining concentration is 9 x 10u207bu2078 M.

https://brainly.com/question/1333307

2. Ksp for FeCOu2083 is 3.07 x 10u207bu00b9u00b9
Ksp for MgCOu2083 is 6.82 x 10u207bu2076
So Feu00b2u207a will precipitated first as solubility product of FeCOu2083 is lower than solubility product of MgCOu2083
Ksp FeCOu2083 = [Feu00b2u207a][COu2083u00b2u207b]
3.07 x 10u207bu00b9u00b9 = (2.3 x 10u207bu00b2) [COu2083u00b2u207b]
[COu2083u00b2u207b] = 1.33 x 10u207bu2079 M to precipitate Feu00b2u207a ions

Ksp MgCOu2083 = [Mgu00b2u207a][COu2083u00b2u207b]
6.82 x 10u207bu2076 = (2.0 x 10u207bu00b2) [COu2083u00b2u207b]
[COu2083u00b2u207b] = 3.4 x 10u207bu2074 M to precipitate the Mgu00b2u207a ions

Ksp FeCOu2083 = [Feu00b2u207a][COu2083u00b2u207b]
3.07 x 10u207bu00b9u00b9 = [Feu00b2u207a] (3.4 x 10u207bu2074)
[Feu00b2u207a] = 9 x 10u207bu2078 M when Mgu00b2u207a ions precipitate