What is the quotient in simplified form? State any restrictions on the variable? \frac{x^2-16}{x^2+5x+6} /\frac{x^2+5x+4}{x^2-2x-8}

Question

What is the quotient in simplified form? State any restrictions on the variable? \frac{x^2-16}{x^2+5x+6} /\frac{x^2+5x+4}{x^2-2x-8}

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2022-04-16T22:02:41+00:00 2 Answers 0

Answers ( 2 )

  1. Charlie
    0
    2022-04-16T22:03:50+00:00

    Answer:

    Full…Solving Rational Equations Quiz part 1.

    1.c. n^2-6/n^2-2 ; n = +/- sqrt5, n= +/- sqrt2

    2.B. 4a/7b^2 , a = 0, b = 0

    3.C. (x-4)^2/(x+3)(x+1) ; x= -4,-3,-2,-1,4

    4.B. (x+1)(x-1)(x^2+1)

    5.A. 7a-49/(a-8)(a+8)

    6.A. 21a-28/(A-6)(a+8)

    7.C. 4x/3x^2+10x+3

    8.C. 3x^2(y+4)/7y

    9.D. -11/3

    10.D. 14

    11. D. 9 mi/h downstream, 6 mi/h upstream

    Step-by-step explanation:

    You’re welcome 🙂

  2. Valerie
    0
    2022-04-16T22:03:52+00:00

    [tex]frac{x^2-16}{x^2+5x+6} / frac{x^2+5x+4}{x^2-2x-8}[/tex]

    We can begin by rearranging this into multiplication:

    [tex]frac{x^2-16}{x^2+5x+6} * frac{x^2-2x-8}{x^2+5x+4}[/tex]

    Now we can factor the numerators and denominators:

    [tex]frac{(x+4)(x-4)}{(x+3)(x+2)} * frac{(x-4)(x+2)}{(x+4)(x+1)}[/tex]

    The factors (x+4) and (x+2) cancel out, leaving us with:

    [tex]frac{(x-4)}{(x+3)} * frac{(x-4)}{(x+1)}[/tex]

    Our answer comes out to be:

    [tex]frac{(x-4)^{2} }{(x+3)(x+1)} [/tex]or [tex]frac{ x^{2} -8x+16}{ x^{2}+4x+3 }[/tex]

    Based on the numerator of the secondfraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are x u2260 -4, -3, -2, -1, 4

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