What is the magnitude of δv12 if the bulb is removed from the socket (i.e. the circuit is not closed)? Question What is the magnitude of δv12 if the bulb is removed from the socket (i.e. the circuit is not closed)? in progress 0 All 1 month 2022-04-08T16:50:41+00:00 2022-04-08T16:50:41+00:00 0 Answers 0
Answers ( 2 )
Since the circuit is incomplete or not closed, no current flows in the circuit. as per ohm’s law , Voltage is directly proportional to current and is given as
V = Voltage = i R where i = current , R = resistance
as no current flows in the circuit, i = 0
the resistance R can not be zero. hence
V = 0 (R)
V = 0 Volts
so the magnitude of the Voltage is zero Volts
If the socket is open after removing the bulb, then the substitute value is
I = 0 A
u0394Vu2081u2082 = IR
= (OA)(2u03a9)
= 0 V