What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second? Question What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second? in progress 0 All 1 month 2022-04-09T04:23:48+00:00 2022-04-09T04:23:48+00:00 2 Answers 0
Answers ( 2 )
Answer:
K = 6.02 x 10u207bu00b9u2079 J
Explanation:
The momentum (p) of an electron is its mass (m) times its speed (v).
p = m x v
v = p / m = (1.05 x 10u207bu00b2u2074 kg.m/s) / 9.11 x 10u207bu00b3u00b9 kg = 1.15 x 10u2076 m/s
We can find the kinetic energy (K) using the following expression.
K = 1/2 x m x vu00b2
K = 1/2 x 9.11 x 10u207bu00b3u00b9 kg x (1.15 x 10u2076 m/s)u00b2
K = 6.02 x 10u207bu00b9u2079 J
Momentum = mv
where m is the mass of an electron and v is the velocity of the electron.
v = momentumu00f7 m
= (1.05x10u2227-24)u00f7(9.1x10u2227-31) = 1,153,846.154 m/s
kinetic energy = (mvu22272)u00f72
= (9.1x10u2227-31×1,153,846.154u22272)u00f72
= (1.21154x10u2227-18)u00f7 2
= 6.05769x10u2227-19 J