What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second?

Question

What is the kinetic energy k of an electron with momentum 1.05×10−24 kilogram meters per second?

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2022-04-09T04:23:48+00:00 2 Answers 0

Answers ( 2 )

  1. Kylie97
    0
    2022-04-09T04:24:51+00:00

    Answer:

    K = 6.02 x 10u207bu00b9u2079 J

    Explanation:

    The momentum (p) of an electron is its mass (m) times its speed (v).

    p = m x v

    v = p / m = (1.05 x 10u207bu00b2u2074 kg.m/s) / 9.11 x 10u207bu00b3u00b9 kg = 1.15 x 10u2076 m/s

    We can find the kinetic energy (K) using the following expression.

    K = 1/2 x m x vu00b2

    K = 1/2 x 9.11 x 10u207bu00b3u00b9 kg x (1.15 x 10u2076 m/s)u00b2

    K = 6.02 x 10u207bu00b9u2079 J

  2. Lilybelle
    0
    2022-04-09T04:25:14+00:00

    Momentum = mv
    where m is the mass of an electron and v is the velocity of the electron.

    v = momentumu00f7 m
    = (1.05x10u2227-24)u00f7(9.1x10u2227-31) = 1,153,846.154 m/s

    kinetic energy = (mvu22272)u00f72
    = (9.1x10u2227-31×1,153,846.154u22272)u00f72
    = (1.21154x10u2227-18)u00f7 2
    = 6.05769x10u2227-19 J

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