What did they say about the man who died from drinking shellac?

Question

What did they say about the man who died from drinking shellac?

in progress 0
2022-05-20T16:33:09+00:00 2 Answers 0

Answers ( 2 )

  1. Morgan
    0
    2022-05-20T16:34:26+00:00

    Answer is:

    He had a lovely finish.

    _______________________________

    Answer 1:

    (x + 4)(x + 2)

    Multiplying the binomials by distributing them,n

    we get;

    = xu00b2 + 2x + 4x + 8

    Adding up the like terms.

    = xu00b2 + 6x + 8

    The answer refers to the letter choice H.

    _______________________________

    Answer 2:

    (x + 7)(x + 1)

    Multiplying the binomials by distributing them,n

    we get;

    = xu00b2 + 7x + 1x + 7

    Adding up the like terms.

    = xu00b2 + 8x + 7

    The answer refers to the letter choice E.

    _______________________________

    Answer 3:

    (x – 6)(x – 3)

    Multiplying the binomials by distributing them,

    we get;

    = xu00b2 – 3x – 6x + 18

    Adding up the like terms.

    = xu00b2 – 9x + 18

    The answer refers to the letter choice H.

    _______________________________

    Answer 4:

    (x + 8)(x – 2)

    Multiplying the binomials by distributing them,

    we get;

    = xu00b2 – 2x + 8x – 16

    Adding up the like terms.

    = xu00b2 + 6x – 16

    The answer refers to the letter choice A.

    _______________________________

    Answer 5:

    (x – 7)(x + 4)

    Multiplying the binomials by distributing them,

    we get;

    = xu00b2 + 4x – 7x – 28

    Adding up the like terms.

    = xu00b2 – 3x – 28

    The answer refers to the letter choice D.

    _______________________________

    Answer 6:

    (x – 2)(x – 9)

    Multiplying the binomials by distributing them,

    we get;

    = xu00b2 – 9x – 2x + 18

    Adding up the like terms.

    = xu00b2 – 11x + 18

    The answer refers to the letter choice A.

    _______________________________

    Answer 7:

    (2u + 4)(u + 1)

    Multiplying the binomials by distributing them,

    we get;

    = 2uu00b2 + 2u + 4u + 4

    Adding up the like terms.

    = 2uu00b2 + 6u + 4

    The answer refers to the letter choice L.

    _______________________________

    Answer 8:

    (3u + 7)(u – 3)

    Multiplying the binomials by distributing them,

    we get;

    = 3uu00b2 – 9u + 7u -21

    Adding up the like terms.

    = 3uu00b2 – 2u – 21

    The answer refers to the letter choice O.

    _______________________________

    Answer 9:

    (4u – 2)(5u – 1)

    Multiplying the binomials by distributing them,

    we get;

    = 20uu00b2 – 4u – 10u + 2

    Adding up the like terms.

    = 20uu00b2 – 14u + 2

    The answer refers to the letter choice V.

    _______________________________

    Answer 10:

    (2u + 1)(9u – 5)

    Multiplying the binomials by distributing them,

    we get;

    = 18uu00b2 – 10u + 9u – 5

    Adding up the like terms.

    = 18uu00b2 – u – 5

    The answer refers to the letter choice E.

    _______________________________

    Answer 11:

    (7u – 4)(3u + 6)

    Multiplying the binomials by distributing them,

    we get;

    = 21uu00b2 + 42u – 12u – 24

    Adding up the like terms.

    = 21uu00b2 + 30u – 24

    The answer refers to the letter choice L.

    _______________________________

    Answer 12:

    (5u – 8)(4u – 4)

    Multiplying the binomials by distributing them,

    we get;

    = 20uu00b2 – 20u – 32u + 32

    Adding up the like terms.

    = 20uu00b2 – 52u + 32

    The answer refers to the letter choice Y.

    _______________________________

    Answer 13:

    (2x + y)(x + 3y) n

    Multiplying the binomials by distributing them,n

    we get;n

    = 2xu00b2 + 6xy + 1xy + 3yu00b2n

    Adding up the like terms.n

    = 2xu00b2 + 7xy + 3yu00b2n

    n

    The answer refers to the letter choice F.n

    _______________________________

    Answer 14:

    (3x – y)(8x – y) n

    Multiplying the binomials by distributing them,n

    we get;n

    = 24xu00b2 – 3xy – 8xy + yu00b2n

    Adding up the like terms.n

    = 24xu00b2 – 11xy + yu00b2n

    n

    The answer refers to the letter choice I.n

    _______________________________

    Answer 15:

    (2x + y)(4x – 3y) n

    Multiplying the binomials by distributing them,n

    we get;n

    = 8xu00b2 – 6xy + 4xy – 3yu00b2n

    Adding up the like terms.n

    = 8xu00b2 – 2xy – 3yu00b2n

    n

    The answer refers to the letter choice N.n

    _______________________________

    Answer 16:

    (5x – 2y)(3x + 4y) n

    Multiplying the binomials by distributing them,n

    we get;n

    = 15xu00b2 + 20xy – 6xy – 8yu00b2n

    Adding up the like terms.n

    = 15xu00b2 + 14xy – 8yu00b2n

    n

    The answer refers to the letter choice I.n

    _______________________________

    Answer 17:

    (7x + 3y)(x + 2y) n

    Multiplying the binomials by distributing them,n

    we get;n

    = 7xu00b2 + 14xy + 3xy + 6yu00b2n

    Adding up the like terms.n

    = 7xu00b2 + 17xy + 6yu00b2n

    n

    The answer refers to the letter choice S.n

    _______________________________

    Answer 18:

    (6x + 6y)(2x – 4y) n

    Multiplying the binomials by distributing them,n

    we get;n

    = 12xu00b2 – 24xy + 12xy – 24yu00b2n

    Adding up the like terms.n

    = 12xu00b2 – 12xy – 24yu00b2n

    n

    The answer refers to the letter choice H.n

    _______________________________

  2. Kylie
    0
    2022-05-20T16:34:41+00:00

    He had a lovely finish

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