What did they say about the man who died from drinking shellac? Question What did they say about the man who died from drinking shellac? in progress 0 All 6 months 2022-05-20T16:33:09+00:00 2022-05-20T16:33:09+00:00 2 Answers 0

## Answers ( 2 )

Answer is:

He had a lovely finish._______________________________

Answer 1:(x + 4)(x + 2)

Multiplying the binomials by distributing them,n

we get;

= xu00b2 + 2x + 4x + 8

Adding up the like terms.

= xu00b2 + 6x + 8The answer refers to the letter choice

H._______________________________

Answer 2:(x + 7)(x + 1)

Multiplying the binomials by distributing them,n

we get;

= xu00b2 + 7x + 1x + 7

Adding up the like terms.

= xu00b2 + 8x + 7The answer refers to the letter choice

E._______________________________

Answer 3:(x – 6)(x – 3)

Multiplying the binomials by distributing them,

we get;

= xu00b2 – 3x – 6x + 18

Adding up the like terms.

= xu00b2 – 9x + 18The answer refers to the letter choice

H._______________________________

Answer 4:(x + 8)(x – 2)

Multiplying the binomials by distributing them,

we get;

= xu00b2 – 2x + 8x – 16

Adding up the like terms.

= xu00b2 + 6x – 16The answer refers to the letter choice

A._______________________________

Answer 5:(x – 7)(x + 4)

Multiplying the binomials by distributing them,

we get;

= xu00b2 + 4x – 7x – 28

Adding up the like terms.

= xu00b2 – 3x – 28The answer refers to the letter choice

D._______________________________

Answer 6:(x – 2)(x – 9)

Multiplying the binomials by distributing them,

we get;

= xu00b2 – 9x – 2x + 18

Adding up the like terms.

= xu00b2 – 11x + 18The answer refers to the letter choice

A._______________________________

Answer 7:(2u + 4)(u + 1)

Multiplying the binomials by distributing them,

we get;

= 2uu00b2 + 2u + 4u + 4

Adding up the like terms.

= 2uu00b2 + 6u + 4The answer refers to the letter choice

L._______________________________

Answer 8:(3u + 7)(u – 3)

Multiplying the binomials by distributing them,

we get;

= 3uu00b2 – 9u + 7u -21

Adding up the like terms.

= 3uu00b2 – 2u – 21The answer refers to the letter choice

O._______________________________

Answer 9:(4u – 2)(5u – 1)

Multiplying the binomials by distributing them,

we get;

= 20uu00b2 – 4u – 10u + 2

Adding up the like terms.

= 20uu00b2 – 14u + 2The answer refers to the letter choice

V._______________________________

Answer 10:(2u + 1)(9u – 5)

Multiplying the binomials by distributing them,

we get;

= 18uu00b2 – 10u + 9u – 5

Adding up the like terms.

= 18uu00b2 – u – 5The answer refers to the letter choice

E._______________________________

Answer 11:(7u – 4)(3u + 6)

Multiplying the binomials by distributing them,

we get;

= 21uu00b2 + 42u – 12u – 24

Adding up the like terms.

= 21uu00b2 + 30u – 24The answer refers to the letter choice

L._______________________________

Answer 12:(5u – 8)(4u – 4)

Multiplying the binomials by distributing them,

we get;

= 20uu00b2 – 20u – 32u + 32

Adding up the like terms.

= 20uu00b2 – 52u + 32The answer refers to the letter choice

Y._______________________________

Answer 13:(2x + y)(x + 3y) n

Multiplying the binomials by distributing them,n

we get;n

= 2xu00b2 + 6xy + 1xy + 3yu00b2n

Adding up the like terms.n

= 2xu00b2 + 7xy + 3yu00b2nn

The answer refers to the letter choice

F.n_______________________________

Answer 14:(3x – y)(8x – y) n

Multiplying the binomials by distributing them,n

we get;n

= 24xu00b2 – 3xy – 8xy + yu00b2n

Adding up the like terms.n

= 24xu00b2 – 11xy + yu00b2nn

The answer refers to the letter choice

I.n_______________________________

Answer 15:(2x + y)(4x – 3y) n

Multiplying the binomials by distributing them,n

we get;n

= 8xu00b2 – 6xy + 4xy – 3yu00b2n

Adding up the like terms.n

= 8xu00b2 – 2xy – 3yu00b2nn

The answer refers to the letter choice

N.n_______________________________

Answer 16:(5x – 2y)(3x + 4y) n

Multiplying the binomials by distributing them,n

we get;n

= 15xu00b2 + 20xy – 6xy – 8yu00b2n

Adding up the like terms.n

= 15xu00b2 + 14xy – 8yu00b2nn

The answer refers to the letter choice

I.n_______________________________

Answer 17:(7x + 3y)(x + 2y) n

Multiplying the binomials by distributing them,n

we get;n

= 7xu00b2 + 14xy + 3xy + 6yu00b2n

Adding up the like terms.n

= 7xu00b2 + 17xy + 6yu00b2nn

The answer refers to the letter choice

S.n_______________________________

Answer 18:(6x + 6y)(2x – 4y) n

Multiplying the binomials by distributing them,n

we get;n

= 12xu00b2 – 24xy + 12xy – 24yu00b2n

Adding up the like terms.n

= 12xu00b2 – 12xy – 24yu00b2nn

The answer refers to the letter choice

H.n_______________________________

He had a lovely finish