Molarity is defined as the number of moles of solute in 1 L of solution mass fo KCl in the solution is – 5.0 g number of moles of KCl – 5.0 g/ 74.5 g/mol = 0.067 mol number of moles of KCl in 100 mL – 0.067 mol therefore number of KCl moles in 1 L – 0.067 / 100 mL x 1000 mL = 0.67 M molarity of KCl is 0.67 M

## Answers ( 2 )

Molarity is defined as the number of moles of solute in 1 L of solution

mass fo KCl in the solution is – 5.0 g

number of moles of KCl – 5.0 g/ 74.5 g/mol = 0.067 mol

number of moles of KCl in 100 mL – 0.067 mol

therefore number of KCl moles in 1 L – 0.067 / 100 mL x 1000 mL = 0.67 M

molarity of KCl is 0.67 M

Answer:The molarity of solution is 0.67 MExplanation:To calculate the molarity of solution, we use the equation:[tex]text{Molarity of the solution}=frac{text{Mass of solute}times 1000}{text{Molar mass of solute}times text{Volume of solution (in mL)}}[/tex]

We are given:Mass of solute (KCl) = 5.0 g

Molar mass of potassium chloride = 74.55 g/mol

Volume of solution = 100 mL

Putting values in above equation, we get:[tex]text{Molarity of solution}=frac{5gtimes 1000}{74.55g/moltimes 100mL}text{Molarity of solution}=0.67M[/tex]

Hence, the molarity of solution is 0.67 M