## The molarity of a solution of 5.0 g of kcl in 100. ml of solution is ________.

Question

The molarity of a solution of 5.0 g of kcl in 100. ml of solution is ________.

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1. Molarity is defined as the number of moles of solute in 1 L of solution
mass fo KCl in the solution is – 5.0 g
number of moles of KCl – 5.0 g/ 74.5 g/mol = 0.067 mol
number of moles of KCl in 100 mL – 0.067 mol
therefore number of KCl moles in 1 L – 0.067 / 100 mL x 1000 mL = 0.67 M
molarity of KCl is 0.67 M

2. Answer: The molarity of solution is 0.67 M

Explanation:

To calculate the molarity of solution, we use the equation:

[tex]text{Molarity of the solution}=frac{text{Mass of solute}times 1000}{text{Molar mass of solute}times text{Volume of solution (in mL)}}[/tex]

We are given:

Mass of solute (KCl) = 5.0 g

Molar mass of potassium chloride = 74.55 g/mol

Volume of solution = 100 mL

Putting values in above equation, we get:

[tex]text{Molarity of solution}=frac{5gtimes 1000}{74.55g/moltimes 100mL}text{Molarity of solution}=0.67M[/tex]

Hence, the molarity of solution is 0.67 M