The average weight of the top 5 fish caught at fishing tournament was 12.3 pounds. Some. Of the weights of the fish are shown in the table

Question

The average weight of the top 5 fish caught at fishing tournament was 12.3 pounds. Some. Of the weights of the fish are shown in the table
the average weight of the top 5 fish

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2022-04-24T07:07:53+00:00 2 Answers 0

Answers ( 2 )

  1. Arianna
    0
    2022-04-24T07:09:03+00:00

    First you would find the total weight of all the 5 fishes that were caught, since 12.3 pounds is the average. You would d this by multiplying 12.3 and 5
    (12.3)(5)=61.5 pounds
    Then in order to find the pound of the unknown fish, you would find the total of the pounds of the other fishes which is given o you in the table and then subtract it from 61.5 which is the total weight of all 5 fishes.
    61.5-46.9=14.6 pounds

  2. Vivian
    0
    2022-04-24T07:09:05+00:00

    I assume that we want to find the weight of the fish caught by Waine S.

    Using our knowledge of means, we will find that it is 14.6 pounds.

    We know that the mean or average of a set of N numbers:

    {xu2081, xu2082, …, xu2099}

    Is given by:

    [tex]M = frac{x_1 + x_2 + … x_n}{N}[/tex]

    Now we know that the mean of the given set is 12.3 pounds

    While the values of the set (in pounds) are:

    {x, 12.8, 12.6, 11.8, 9.7}

    So we have N = 5.

    Then writing the average/mean equation we get:

    [tex] 12.3 = frac{x + 12.8 + 12.6 + 11.8 + 9.7}{5}[/tex]

    Now let’s solve that for x.

    [tex] 12.3 = frac{x + 12.8 + 12.6 + 11.8 + 9.7}{5} = frac{x + 46.9}{5} 12.3 cdot 5 = x + 46.961.5 = x + 46.961.5 – 46.9 = x = 14.6[/tex]

    From this, we can conclude that the weight of the fish that Wayne S. caught is 14.6 pounds.

    If you want to learn more, you can read:

    https://brainly.com/question/23562402

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45:5+15*4 = ? ( )