## The average weight of the top 5 fish caught at fishing tournament was 12.3 pounds. Some. Of the weights of the fish are shown in the table

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## Answers ( 2 )

First you would find the total weight of all the 5 fishes that were caught, since 12.3 pounds is the average. You would d this by multiplying 12.3 and 5

(12.3)(5)=61.5 pounds

Then in order to find the pound of the unknown fish, you would find the total of the pounds of the other fishes which is given o you in the table and then subtract it from 61.5 which is the total weight of all 5 fishes.

61.5-46.9=14.6 pounds

I assume that we want to find the

weightof the fish caught by Waine S.Using our knowledge of means, we will find that it is

14.6 pounds.We know that the

meanoraverageof a set of N numbers:{xu2081, xu2082, …, xu2099}

Is given by:

[tex]M = frac{x_1 + x_2 + … x_n}{N}[/tex]

Now we know that the

meanof the given set is 12.3 poundsWhile the values of the set (in pounds) are:

{x, 12.8, 12.6, 11.8, 9.7}

So we have N = 5.

Then writing the

average/meanequation we get:[tex] 12.3 = frac{x + 12.8 + 12.6 + 11.8 + 9.7}{5}[/tex]

Now let’s solve that for x.

[tex] 12.3 = frac{x + 12.8 + 12.6 + 11.8 + 9.7}{5} = frac{x + 46.9}{5} 12.3 cdot 5 = x + 46.961.5 = x + 46.961.5 – 46.9 = x = 14.6[/tex]

From this, we can conclude that the

weightof the fish that Wayne S. caught is 14.6 pounds.If you want to learn more, you can read:

https://brainly.com/question/23562402