On the math portion of the sat, the mean score was 510 with a standard deviation of 95. on the verbal portion, the mean score was 530 with a
Question
On the math portion of the sat, the mean score was 510 with a standard deviation of 95. on the verbal portion, the mean score was 530 with a standard deviation of 85. you now know the mean of the combined score is 1040 with a standard deviation of 127.48. given that these are normal distributions, you can do normal calculations with the combined statistics. what is the probability that a random student scored 1100 or better?
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2022-04-09T02:03:28+00:00
2022-04-09T02:03:28+00:00 0 Answers
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the probability that a random student scored 1100 or better will be found as follows:
z-score is given by:
z=(x-u03bc)/u03c3
where:
u03bc-mean
u03c3-standard deviation
thus the z-score for this situation will be:
z=(1100-1040)/127.48
z=0.4707
Thus:
P(x>1100)=1-P(z<0.4707)=1-0.6808=0.3192