Light of wavelength 600 nm illuminates a diffraction grating. the second-order maximum is at angle 39.5 ∘. part a how many lines per millime

Question

Light of wavelength 600 nm illuminates a diffraction grating. the second-order maximum is at angle 39.5 ∘. part a how many lines per millimeter does this grating have?

in progress 0
2022-04-16T01:00:04+00:00 2 Answers 0

Answers ( 2 )

  1. Claire
    0
    2022-04-16T01:02:00+00:00

    The number of lines per millimeter that the grating has is : u2248 530 lines

    Given data :

    light wavelength = 600 nm

    second order maximum angle ( x ) = 39.5u00b0

    order of maximum = 2

    Determine the number of lines the grating will have

    We will apply diffraction equation

    [tex]d*sinx = m*wavelength[/tex] — ( 1 )

    where : d = spacing of lines, x = 39.5u00b0, m = 2

    Insert values into equation ( 1 ) above

    d * Sin ( 39.5 ) = 2 * 600 * 10u207bu2079

    therefore ; d = 1.88656 * 10u207bu2076 m

    Final step : determine the number of lines per mm

    Number of lines per mm

    = 0.001 / d

    = 0.001 / (1.88656 * 10u207bu2076 ) u2248 530 lines

    Hence we can conclude that The number of lines per millimeter that the grating has is u2248 530 lines

    Learn more about grating : https://brainly.com/question/25804706

  2. Hailey
    0
    2022-04-16T01:02:02+00:00

    Diffraction equation applies in this case:

    d*Sin x = m*wavelength, where d = spacing of lines, x = angle = 39.5u00b0, m = order of maximum = 2

    Substituting;
    d* Sin 39.5 = 2*600*10^-9
    d = (2*600*10^-9)/Sin 39.5 = 1.88656*10^-6 m

    In 1 mm (or 0.001 m), the number of lines is given as;
    Number of lines = 0.001/d = 0.001/(1.88656*10^-6) = 530.065u2248 530 lines

Leave an answer

Browse
Browse

45:5+15*4 = ? ( )