How to find the sum of the squares of the lengths of the legs of a triangle of a=(-6,11) b=(2,8) c=(-1,0)?

Question

How to find the sum of the squares of the lengths of the legs of a triangle of a=(-6,11) b=(2,8) c=(-1,0)?

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2022-04-10T20:52:11+00:00 1 Answer 0

Answers ( 1 )

  1. Hailey
    0
    2022-04-10T20:53:32+00:00

    we have that
    a=(-6,11) b=(2,8) c=(-1,0)

    step 1
    find the distances with the formula
    d=u221a[(y2-y1)u00b2+(x2-x1)u00b2]

    distance ab
    dab=u221a[(8-11)u00b2+(2+6)u00b2]—-> dab=u221a73 units

    distance bc
    dbc=u221a[(0-8)u00b2+(-1-2)u00b2]—-> bc=u221a73 units

    distance ac
    dac=u221a[(0-11)u00b2+(-1+6)u00b2]—-> dac=u221a146 units

    the legs are
    ab=u221a73 units
    bc=u221a73 units

    the hypotenuse is
    ac=u221a146 units

    the sum of the squares of the lengths of the legs is
    (u221a73)u00b2+(u221a73)u00b2=73+73—–> 146

    the answer is
    146

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