How to find the sum of the squares of the lengths of the legs of a triangle of a=(-6,11) b=(2,8) c=(-1,0)? Question How to find the sum of the squares of the lengths of the legs of a triangle of a=(-6,11) b=(2,8) c=(-1,0)? in progress 0 All 1 month 2022-04-10T20:52:11+00:00 2022-04-10T20:52:11+00:00 1 Answer 0

## Answers ( 1 )

we have that

a=(-6,11) b=(2,8) c=(-1,0)

step 1

find the distances with the formula

d=u221a[(y2-y1)u00b2+(x2-x1)u00b2]

distance ab

dab=u221a[(8-11)u00b2+(2+6)u00b2]—-> dab=u221a73 units

distance bc

dbc=u221a[(0-8)u00b2+(-1-2)u00b2]—-> bc=u221a73 units

distance ac

dac=u221a[(0-11)u00b2+(-1+6)u00b2]—-> dac=u221a146 units

the legs are

ab=u221a73 units

bc=u221a73 units

the hypotenuse is

ac=u221a146 units

the sum of the squares of the lengths of the legs is

(u221a73)u00b2+(u221a73)u00b2=73+73—–> 146

the answer is146