## A balloon rubbed against denim gains a charge of −8.0 µc. what is the electric force between the balloon and the denim when the two are sepa

Question

A balloon rubbed against denim gains a charge of −8.0 µc. what is the electric force between the balloon and the denim when the two are separated by a distance of 6.0 cm? (assume that the charges are located at a point.) the value of the coulomb constant is 8.98755 x 109 n · m2 /c 2 . include direction of the force. answer in units of n.

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2022-05-13T00:07:10+00:00
2022-05-13T00:07:10+00:00 2 Answers
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## Answers ( 2 )

From Coulombs law,

F= {k*Q1*Q2}/d^2

Where, F= electric force, Q1&Q2 = charges in respective surfaces, d= distnace of separation.

In the current scenario, Q1= -8 micro C, Q2 = +8 micro C, d= 6 cm = 0.06 m, k= Coulomb’s constant = 8.98755*10^9 N.m^2/C^2

Therefore,

F= {8.98755*10^9*-8*8}/0.06^2 = -1.6*10^14 N

-ve sign shows that the force is towards the denim.

The

electric forcebetween theballoonand thedenimis159.78 N.The given parameters:

The

electric forcebetween theballoonand thedenimis calculated by applying Coulomb’s law for a point charge;[tex]F = frac{kq^2}{r^2} F = frac{8.98755 times 10^9 times (8times 10^{-6})^2}{(6times 10^{-2})^2} F = 159.78 N[/tex]

Thus, the

electric forcebetween theballoonand thedenimis159.78 N.Learn more about

Coulomb’s lawhere: https://brainly.com/question/506926